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-20.8x^2+3.7x+2.9=x
We move all terms to the left:
-20.8x^2+3.7x+2.9-(x)=0
We add all the numbers together, and all the variables
-20.8x^2+2.7x+2.9=0
a = -20.8; b = 2.7; c = +2.9;
Δ = b2-4ac
Δ = 2.72-4·(-20.8)·2.9
Δ = 248.57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.7)-\sqrt{248.57}}{2*-20.8}=\frac{-2.7-\sqrt{248.57}}{-41.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.7)+\sqrt{248.57}}{2*-20.8}=\frac{-2.7+\sqrt{248.57}}{-41.6} $
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